A small hole is cut in the bottom of a water storage tank.The initial depth of the water is 8.00 m.If the diameter of the small hole in the bottom of the tank is 1.00 cm,then what is the flow rate of the water leaving the tank? A) 9.83 $\times$ 10^-4 m³/s B) 8.75 $\times$ 10^-4 m³/s C) 8.21 $\times$ 10^-4 m³/s D) 7.45 $\times$ 10^-4 m³/s E) 7.21 $\times$ 10^-4 m³/s

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Quizplus · Accepted Answer

The flow rate can be calculated using Torricelli's Law: Q = A * sqrt(2gh), where A is the area of the hole, g is the acceleration due to gravity, and h is the height of the water. The area A = π*(0.005 m)^2. Substituting the values, we get the flow rate as approximately 9.83 * 10^-4 m^3/s.

A Small Hole Is Cut in the Bottom of a Water