The pressure at what depth in seawater (1025 kg/m³)is equivalent to that at a depth of 10.0 m in fresh water (1000 kg/m³)? A) 10.2 m B) 9.8 m C) 10.3 m D) 9.7 m

Question

Quizplus · Accepted Answer

The pressure in a fluid is given by P = ρgh, where ρ is the density of the fluid, g is the acceleration due to gravity, and h is the depth. Since the depth in fresh water is given as h = 10.0 m and the density of fresh water is ρ_freshwater = 1000 kg/m^3, the pressure at this depth is P_freshwater = 1000 kg/m^3 × 9.81 m/s^2 × 10.0 m = 98100 Pa. 
To find the depth in seawater that would have the same pressure, we can set the pressure in seawater equal to this and solve for the depth: 
P_seawater = ρ_seawater × g × h_seawater

98100 Pa = 1025 kg/m^3 × 9.81 m/s^2 × h_seawater

h_seawater = 98100 Pa / (1025 kg/m^3 × 9.81 m/s^2) = 9.8 m

Therefore, the pressure at a depth of 9.8 m in seawater is equivalent to the pressure at a depth of 10.0 m in fresh water. Answer B is correct.

The Pressure at What Depth in Seawater (1025 Kg/m3)is Equivalent

The Pressure at What Depth in Seawater (1025 Kg/m³)is Equivalent