A reaction was experimentally determined to follow the rate law, Rate = k[A]² where k = 0.456 s^-1M^-1. Starting with [A]_o = 0.500 M, how many seconds will it take for [A]_t = 0.250 M

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Quizplus · Accepted Answer

For a second-order reaction, the integrated rate law is 1/[A]_t = kt + 1/[A]_o. Plugging in the values: 1/0.250 = 0.456 * t + 1/0.500. Solving for t gives t = 4.39 s.

A Reaction Was Experimentally Determined to Follow the Rate Law