What is the pressure (mmHg) of the sample of gas trapped in the open-tube mercury manometer shown below if atmospheric pressure is 742 mmHg and h = 16.7 cm
A) 375 mmHg
B) 475 mmHg
C) 575 mmHg
D) 675 mmHg
E) None of the Above

Question

What is the pressure (mmHg) of the sample of gas trapped in the open-tube mercury manometer shown below if atmospheric pressure is 742 mmHg and h = 16.7 cm 
A) 375 mmHg 
B) 475 mmHg 
C) 575 mmHg 
D) 675 mmHg 
E) None of the Above

Quizplus · Accepted Answer

The pressure of the gas can be calculated using the equation:

Pgas = Patm + ρgh

where Pgas is the pressure of the gas, Patm is the atmospheric pressure, ρ is the density of the mercury, g is the acceleration due to gravity, and h is the height difference between the two arms of the manometer.

Substituting the given values:

Pgas = 742 + (13.6 x 9.81 x 0.167)
Pgas = 574.88 ≈ 575 mmHg

Therefore, the pressure of the gas trapped in the open-tube mercury manometer is approximately 575 mmHg. The correct answer is C.

What Is the Pressure (MmHg) of the Sample of Gas