In the Hardy-Weinberg equation,p² + 2pq + q² = 1.If the dominant allele frequency is 0.8 what percent of the population will be heterozygous?

Name: In the Hardy-Weinberg equation,p 2 + 2pq + q 2 = 1.If the dominant allele frequency is 0.8 what percent of the population will be heterozygous?
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Quizplus · Accepted Answer

The frequency of the dominant allele (p) is 0.8, so the frequency of the recessive allele (q) is 0.2. The heterozygous frequency is calculated as 2pq = 2(0.8)(0.2) = 0.32, or 32%.

In the Hardy-Weinberg Equation,p2 + 2pq + Q2 = 1

In the Hardy-Weinberg Equation,p² + 2pq + Q² = 1