In the Hardy-Weinberg equation,p² + 2pq + q² = 1.If the dominant allele frequency is 0.8,what percent of the population will be homozygous recessive?

Name: In the Hardy-Weinberg equation,p 2 + 2pq + q 2 = 1.If the dominant allele frequency is 0.8,what percent of the population will be homozygous recessive?
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Quizplus · Accepted Answer

The frequency of the recessive allele (q) is 1 - 0.8 = 0.2. The percentage of the population that is homozygous recessive is q^2 = (0.2)^2 = 0.04, or 4%.

In the Hardy-Weinberg Equation,p2 + 2pq + Q2 = 1

In the Hardy-Weinberg Equation,p² + 2pq + Q² = 1