Given a normal distribution of test scores with
= 80,s²= 49,what is the z score corresponding to a test score of 95?

Question

Given a normal distribution of test scores with = 80,s²= 49,what is the z score corresponding to a test score of 95?

Quizplus · Accepted Answer

To find the z-score of a test score of 95 in a normal distribution with mean=80 and standard deviation=7, we use the formula:

z = (x - mu) / sigma

where x is the test score, mu is the mean, and sigma is the standard deviation.

Plugging in the values, we get:

z = (95 - 80) / 7 = 2.14

Therefore, the z-score corresponding to a test score of 95 is 2.14. The correct choice is C.

Given a Normal Distribution of Test Scores with