An instructor has given his final exam,and scores are approximately normally distributed.Nancy scores a 90 and Ronald scores a 75.The characteristics of the distribution are as follows:
= 85,s² = 36.What is Nancy's z score?

Question

Quizplus · Accepted Answer

We can use the formula for z-score:

z = (x - μ) / σ

where: 
- x is the individual score (Nancy's score of 90 in this case)
- μ is the mean (given as 85)
- σ is the standard deviation (given as 6)

Plugging in the values:

z = (90 - 85) / 6 = 0.83

So Nancy's z-score is 0.83. The answer is (C).

An Instructor Has Given His Final Exam,and Scores Are Approximately