What volume of 0.233 M H2SO4 is needed to react exactly with 15.0 grams of aluminum? 2Al(s) + 3H2SO4(aq) → Al2(SO4) 3(aq) + 3H2(g)
A) 2.39 L
B) 0.556 L
C) 0.864 L
D) 4.22 L
E) 3.58 L
Correct Answer:
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