What volume of 0.200 M H₂SO₄ solution is required to react exactly with 50.0 mL of 0.100 M KOH? H₂SO₄(aq) + 2KOH(aq) → 2H₂O(l) + K₂SO₄(aq)

Question

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Use the equation: n(H₂SO₄) = n(KOH) n(KOH) = C x V = 0.100 mol/L x 0.0500 L = 0.00500 mol n(H₂SO₄) = 0.00500 mol / 2 = 0.00250 mol Use the equation: n = C x V V(H₂SO₄) = n(H₂SO₄) / C = 0.00250 mol / 0.200 mol/L = 0.0125 L = 12.5 mL of the H₂SO₄ solution is required.

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