What mass of precipitate forms when 25.0 mL of 0.147 M NiCl₂ solution reacts with excess sodium phosphate according to the given balanced chemical equation. 3NiCl₂(aq) + 2Na₃PO₄(aq) → Ni₃(PO₄)₂(s) + 6NaCl(aq)

Question

Quizplus · Accepted Answer

The moles of NiCl2 are calculated using its concentration and volume. Using the stoichiometry of the reaction, the moles of Ni3(PO4)2 formed are determined. The molar mass of Ni3(PO4)2 is used to find the mass of the precipitate.

What Mass of Precipitate Forms When 25