The combustion of pentane produces heat according to the following thermochemical equation.C₅H ₁₂(l) + 8O₂(g) → 5CO₂(g) + 6H₂O(l) heat of reaction = −3510 kJ/mol How many grams of CO₂ is produced per 2.50 × 10³ kJ of heat released?

Question

Quizplus · Accepted Answer

The heat of reaction is -3510 kJ/mol, meaning 3510 kJ is released per mole of pentane combusted. For 2.50 × 10³ kJ, the moles of pentane combusted is (2.50 × 10³ kJ) / (3510 kJ/mol) = 0.712 mol. Since 5 moles of CO₂ are produced per mole of pentane, 0.712 mol × 5 = 3.56 mol of CO₂ is produced. The molar mass of CO₂ is 44.01 g/mol, so 3.56 mol × 44.01 g/mol = 157 g of CO₂.

The Combustion of Pentane Produces Heat According to the Following