Determine the freezing point of a solution formed by dissolving 0.187 moles of glucose in 456 grams of water.(For water, K_f = 1.86°C/m)

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Quizplus · Accepted Answer

The freezing point depression can be calculated using the formula ΔTf = i * Kf * m, where ΔTf is the freezing point depression, i is the van't Hoff factor (which is 1 for glucose, a non-electrolyte), Kf is the molal freezing point depression constant for water (1.86°C/m), and m is the molality of the solution. First, calculate the molality (moles of solute per kilogram of solvent): molality = 0.187 moles / 0.456 kg = 0.410 m. Then, ΔTf = 1 * 1.86°C/m * 0.410 m = 0.7626°C, which rounds to −0.763°C, indicating a freezing point depression of 0.763°C. Thus, the freezing point of the solution is 0°C - 0.763°C = −0.763°C.

Determine the Freezing Point of a Solution Formed by Dissolving