Determine the boiling point of a solution formed by dissolving 0.312 moles of sugar in 275 grams of water.(For water, K_b = 0.512°C/m)

Question

Quizplus · Accepted Answer

First, we need to calculate the molality of the solution:
molality = moles of solute / mass of solvent in kg
mass of solvent = 275 g = 0.275 kg
molality = 0.312 mol / 0.275 kg = 1.13 mol/kg

Next, we can use the equation:
ΔTb = i * Kb * molality
where ΔTb is the boiling point elevation, i is the van't Hoff factor (assume 1 for sugar), and Kb is the boiling point constant for water.

From the given data, Kb = 0.512°C/m, so:
ΔTb = 1 * 0.512°C/m * 1.13 mol/kg = 0.58056°C

Finally, we can calculate the new boiling point:
new boiling point = normal boiling point of water + ΔTb
normal boiling point of water = 100°C
new boiling point = 100°C + 0.58056°C = 100.58056°C

Therefore, the answer is B) 100.581°C.

Determine the Boiling Point of a Solution Formed by Dissolving