A solution was prepared such that the initial concentrations of Cu²⁺(aq)and CN^-(aq)were 0.0120 M and 0.0400 M, respectively. These ions react according to the following chemical equation
Cu²⁺(aq)+ 4CN^-(aq) Cd(CN)₄^2-(aq)K_c = 1.0 * 10²⁵
What will be the concentration of CN^-(aq)at equilibrium?

Question

A solution was prepared such that the initial concentrations of Cu²⁺(aq)and CN^-(aq)were 0.0120 M and 0.0400 M, respectively. These ions react according to the following chemical equation
Cu²⁺(aq)+ 4CN^-(aq)

A solution was prepared such that the initial concentrations of Cu<sup>2+</sup>(aq)and CN<sup>-</sup>(aq)were 0.0120 M and 0.0400 M, respectively. These ions react according to the following chemical equation Cu<sup>2+</sup>(aq)+ 4CN<sup>-</sup>(aq) Cd(CN)<sub>4</sub><sup>2-</sup>(aq)K<sub>c</sub> = 1.0 * 10<sup>25</sup> <sup> </sup>What will be the concentration of CN<sup>-</sup>(aq)at equilibrium?

Cd(CN)₄^2-(aq)K_c = 1.0 * 10²⁵
What will be the concentration of CN^-(aq)at equilibrium?

Quizplus · Accepted Answer

The Answer of A solution was prepared such that the initial concentrations of Cu²⁺(aq)and CN^-(aq)were 0.0120 M and 0.0400 M, respectively. These ions react according to the following chemical equation Cu²⁺(aq)+ 4CN^-(aq) Cd(CN)₄^2-(aq)K_c = 1.0 * 10²⁵ What will be the concentration of CN^-(aq)at equilibrium?

A Solution Was Prepared Such That the Initial Concentrations of Cu2+(aq)and

A Solution Was Prepared Such That the Initial Concentrations of Cu²⁺(aq)and