Ethanol and acetic acid react to form ethyl acetate and water according to the following chemical equation:
C₂H₅OH(l)+ CH₃COOH(l) CH₃COOC₂H₅(l)+ H₂O(l)
When two moles each of ethanol and acetic acid are combined, equilibrium is reached when two-thirds of a mole of each of the reactants remains. Calculate the equilibrium constant for this reaction assuming total volume does not change during the course of the reaction. (Note: since water is not the solvent, but rather a product of the reaction, [H₂O] changes during the course of the reaction, so it should be included in the equilibrium constant expression.)

Question

Ethanol and acetic acid react to form ethyl acetate and water according to the following chemical equation:
C₂H₅OH(l)+ CH₃COOH(l)

Ethanol and acetic acid react to form ethyl acetate and water according to the following chemical equation: C<sub>2</sub>H<sub>5</sub>OH(l)+ CH<sub>3</sub>COOH(l) CH<sub>3</sub>COOC<sub>2</sub>H<sub>5</sub>(l)+ H<sub>2</sub>O(l) When two moles each of ethanol and acetic acid are combined, equilibrium is reached when two-thirds of a mole of each of the reactants remains. Calculate the equilibrium constant for this reaction assuming total volume does not change during the course of the reaction. (Note: since water is not the solvent, but rather a product of the reaction, [H<sub>2</sub>O] changes during the course of the reaction, so it should be included in the equilibrium constant expression.)

CH₃COOC₂H₅(l)+ H₂O(l)
When two moles each of ethanol and acetic acid are combined, equilibrium is reached when two-thirds of a mole of each of the reactants remains. Calculate the equilibrium constant for this reaction assuming total volume does not change during the course of the reaction. (Note: since water is not the solvent, but rather a product of the reaction, [H₂O] changes during the course of the reaction, so it should be included in the equilibrium constant expression.)

Quizplus · Accepted Answer

The Answer of Ethanol and acetic acid react to form ethyl acetate and water according to the following chemical equation: C₂H₅OH(l)+ CH₃COOH(l) CH₃COOC₂H₅(l)+ H₂O(l) When two moles each of ethanol and acetic acid are combined, equilibrium is reached when two-thirds of a mole of each of the reactants remains. Calculate the equilibrium constant for this reaction assuming total volume does not change during the course of the reaction. (Note: since water is not the solvent, but rather a product of the reaction, [H₂O] changes during the course of the reaction, so it should be included in the equilibrium constant expression.)

Ethanol and Acetic Acid React to Form Ethyl Acetate and Water