The Equilibrium Constant at 427°C for the Reaction N₂(g)+ 3H₂(g) $\rarr$

The equilibrium constant at 427°C for the reaction N₂(g) + 3H₂(g) $\rarr$ 2NH₃(g) is K_p = 9.4 * 10^-5. Calculate the value of $\Delta$ G° for the reaction under these conditions.

A) -33 kJ/mol
B) -54 kJ/mol
C) 54 kJ/mol
D) 33 kJ/mol
E) 1.3 J/mol