For a particular process that is carried out at constant pressure,q = 125 kJ and w = -15 kJ.Therefore,

Name: For a particular process that is carried out at constant pressure,q = 125 kJ and w = -15 kJ.Therefore,
Brand: Quizplus
Rating: 4.9 (52 reviews)

Question

Quizplus · Accepted Answer

The change in internal energy (ΔE) is given by the formula ΔE = q + w. Here, q = 125 kJ and w = -15 kJ, so ΔE = 125 kJ - 15 kJ = 110 kJ. The change in enthalpy (ΔH) at constant pressure is equal to the heat exchanged, q, which is 125 kJ.

For a Particular Process That Is Carried Out at Constant