The heat of vaporization of water at 100°C is 40.66 kJ/mol.Calculate the quantity of heat that is absorbed/released when 5.00 g of steam condenses to liquid water at 100°C.

Question

Quizplus · Accepted Answer

The heat released when steam condenses is calculated using the formula: q = n * ΔHvap. First, convert 5.00 g of steam to moles (5.00 g / 18.02 g/mol = 0.277 mol). Then, multiply by the heat of vaporization: 0.277 mol * 40.66 kJ/mol = 11.3 kJ. Since condensation releases heat, 11.3 kJ are released.

The Heat of Vaporization of Water at 100°C Is 40