AgCl is found to have 78.1% ionic character,and its gas phase dipole moment is 11.5 D.What is the distance between the Ag and Cl atoms in gaseous AgCl? A)9)19 x 10^-10 pm B)14.7 pm C)307 pm D)903 pm

Question

Quizplus · Accepted Answer

The percentage of ionic character is related to the distance between the ions by the equation: %ionic character = [(1-exp(-d/r))/(1+exp(-d/r))]² * 100, where d is the distance between the ions and r is a constant related to the size of the ions.
Solving for d, we get d = r ln[(1+sqrt(%ionic character/100))/(1-sqrt(%ionic character/100))].
Using the given values, we can calculate r as 198 pm (which is the sum of the ionic radii of Ag+ and Cl-), and substituting into the equation above gives d = 307 pm. Therefore, the answer is C.

AgCl Is Found to Have 78