What is the molality of a glucose solution prepared by dissolving 18.0 g of glucose,C₆H₁₂O₆,in 125.9 g of water? A)7)94 × 10^-4 m B)0)143 m C)0)695 m D)0)794 m

Question

Quizplus · Accepted Answer

Step 1: Calculate the moles of glucose
Molar mass of glucose (C6H12O6) = 180.18 g/mol
Number of moles of glucose = 18.0 g / 180.18 g/mol = 0.1 mol

Step 2: Calculate the mass of water in kg
Mass of water = 125.9 g = 0.1259 kg

Step 3: Calculate the molality
Molality = moles of solute / mass of solvent in kg
Molality = 0.1 mol / 0.1259 kg = 0.794 m

Therefore, the molality of the glucose solution is 0.794 m. The correct answer is D.

What Is the Molality of a Glucose Solution Prepared by Dissolving