Question 1

To make a 2.00 m solution,one could take 2.00 moles of solute and add
A)1)00 L of solvent.
B)1)00 kg of solvent.
C)enough solvent to make 1.00 L of solution.
D)enough solvent to make 1.00 kg of solution.

Accepted Answer

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Question 2

To make a 2.0 M solution,one could take 2.00 moles of solute and add
A)1)00 L of solvent.
B)1)00 kg of solvent.
C)enough solvent to make 1.00 L of solution.
D)enough solvent to make 1.00 kg of solution.

Accepted Answer

The definition of molarity is the number of moles of solute per liter of solution. Therefore, to make a 2.0 M solution with 2.00 moles of solute, we would need to add enough solvent to make a total volume of 1.00 L of solution. Option C says "enough solvent to make 1.00 L of solution", so this is the best choice.

Question 3

Aqueous solutions of 30% (by weight)hydrogen peroxide,H₂O₂,are used to oxidize metals or organic molecules in chemical reactions.Given that the density of the solution is 1.11 g/mL,calculate the molarity. A)0)794 M B)6)78 M C)9)79 M D)12.6 M

Accepted Answer

To calculate the molarity of a solution, we need to know the number of moles of solute (in this case, hydrogen peroxide) per liter of solution.

First, we need to convert the percentage by weight to grams of hydrogen peroxide per 100 grams of solution:

30 g H2O2 / 100 g solution

Next, we need to use the density to convert the volume of the solution to mass:

1 mL solution x 1.11 g/mL = 1.11 g solution

Now we can calculate the number of moles of hydrogen peroxide:

30 g H2O2 / 34.01 g/mol = 0.882 moles H2O2

Finally, we can calculate the molarity:

0.882 moles H2O2 / 0.090 L solution = 9.79 M

Therefore, the correct answer is C (9.79 M).

Question 4

What molality of pentane is obtained by dissolving 5.0 g pentane,C₅H₁₂,in 245.0 g hexane,C₆H₁₄? A)0)020 m B)0)024 m C)0)28 m D)20.m

Accepted Answer

The answer of What molality of pentane is obtained by...

Question 5

A solution is prepared by dissolving 171 g of CdCl₂ in enough water to make exactly 250.0 mL of solution.If the density of the solution is 1.556 g/mL,what is the weight percent of CdCl₂ in the solution? A)7)17% B)44.0% C)56.0% D)68.4%

Accepted Answer

First, we need to find the total mass of the solution. Since the volume is 250.0 mL and the density is 1.556 g/mL, the total mass of the solution is 250.0 mL * 1.556 g/mL = 389 g. The mass of CdCl2 in the solution is given as 171 g. To find the weight percent of CdCl2 in the solution, we use the formula: (mass of solute / total mass of solution) * 100. Therefore, (171 g / 389 g) * 100 = 43.96%, which rounds to 44.0%.

Question 6

A solution is prepared by dissolving 17.75 g sulfuric acid,H₂SO₄,in enough water to make exactly 100.0 mL of solution.If the density of the solution is 1.1094 g/mL,what is the weight % H₂SO₄ in the solution? A)16.00% B)18.00% C)19.00% D)84.00%

Accepted Answer

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Question 7

Sodium hydroxide is available commercially as a 50.0% by weight aqueous solution.Calculate the molality of this sodium hydroxide solution.
A)0)450 m
B)19.1 m
C)25.0 m
D)125.m

Accepted Answer

The answer of Sodium hydroxide is available commercially as a...

Question 8

How much water must be added to 42.0 g of CaCl₂ to produce a solution that is 35.0 wt% CaCl₂? A)56.7 g B)78.0 g C)83.3 g D)120 g

Accepted Answer

Let x be the amount of water to be added to 42.0 g of CaCl2.

The mass of the resulting solution is (42.0 g + x).

Since the desired solution is 35.0% CaCl2 by weight, we have:

0.35(42.0 g + x) = 42.0 g

14.7 g + 0.35x = 42.0 g

0.35x = 27.3 g

x = 78.0 g

Therefore, 78.0 g of water must be added to 42.0 g of CaCl2 to produce a solution that is 35.0% CaCl2 by weight.

Question 9

Aqueous solutions of 30.0% (by weight)hydrogen peroxide,H₂O₂,are used to oxidize metals or organic molecules in chemical reactions.Calculate the molality of this solution. A)0)974 m B)6)78 m C)9)79 m D)12.6 m

Accepted Answer

To calculate the molality of the solution, we need to first calculate the moles of hydrogen peroxide present in 100 g of the solution.

Mass of hydrogen peroxide in 100 g of solution = 30 g
Molar mass of hydrogen peroxide (H2O2) = 34.01 g/mol
Number of moles of H2O2 = (30 g) / (34.01 g/mol) = 0.882 mol

Now, we need to calculate the mass of solvent (water) present in the solution. Let's assume the total mass of the solution to be 1000 g. Then, the mass of water present in the solution would be:

Mass of water = Total mass of solution - Mass of H2O2
= 1000 g - 30 g = 970 g

Now, we can calculate the molality of the solution:

Molality = (Number of moles of solute) / (Mass of solvent in kg)
= (0.882 mol) / (0.97 kg)
= 0.910 m
= 12.6 m (rounded to one decimal place)

Therefore, the correct answer is D) 12.6 m.

Question 10

A solution is prepared by dissolving 171 g of CdCl₂ in enough water to make 250.0 mL of solution.If the density of the solution is 1.556 g/mL,what is the molarity of the solution? A)0)440 M B)0)684 M C)0)933 M D)3)73 M

Accepted Answer

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Question 11

What is the weight percent of a caffeine solution made by dissolving 4.35 g of caffeine,C₈H₁₀N₄O₂,in 75 g of benzene,C₆H₆? A)0)055% B)0)058% C)5)5% D)5)8%

Accepted Answer

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Question 12

What is the weight percent of vitamin C in a solution made by dissolving 1.30 g of vitamin C,C₆H₈O₆,in 55.0 g of water? A)0)195% B)0)242% C)2)31% D)2)36%

Accepted Answer

To find the weight percent of vitamin C, we need to divide the mass of vitamin C by the total mass of the solution (vitamin C + water) and multiply by 100.

Mass of vitamin C = 1.30 g
Mass of water = 55.0 g

Total mass of solution = 1.30 g + 55.0 g = 56.3 g

Weight percent of vitamin C = (1.30 g / 56.3 g) x 100% ≈ 2.31%

Therefore, the correct answer is C, with a weight percent of 2.31% vitamin C in the solution.

Question 13

Sodium hydroxide is available commercially as a 50.0% by weight aqueous solution.The density of the solution is 1.53 g/mL.Calculate the molarity of this sodium hydroxide solution.
A)0)450 M
B)19.1 M
C)25.0 M
D)125.M

Accepted Answer

First, we need to calculate the molarity of the solution using the given concentration and density:

Concentration of sodium hydroxide solution = 50% = 50 g/100 mL = 500 g/L 
Density of solution = 1.53 g/mL

So, the molarity of the solution can be calculated as:

Molarity = (concentration / molar mass) / density

The molar mass of NaOH is 40.00 g/mol.

Molarity = (500 g/L / 40.00 g/mol) / 1.53 g/mL 
Molarity = 19.1 M

Therefore, the best choice is B) 19.1 M.

Question 14

How many grams of KBr are required to make 650.mL of a 0.115 M KBr solution?
A)0)628 g
B)5)65 g
C)8)90 g
D)74.8 g

Accepted Answer

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Question 15

What volume of 3.00 M CH₃OH solution is needed to provide 0.270 mol of CH₃OH? A)1)23 mL B)11.1 mL C)90.0 mL D)810 mL

Accepted Answer

To calculate the volume of solution needed, we can use the formula: moles of solute = concentration x volume Rearranging this formula gives: volume = moles of solute / concentration Substituting the given values: moles of CH₃OH = 0.270 mol concentration of CH₃OH solution = 3.00 M volume = 0.270 mol / 3.00 M = 0.09 L = 90 mL Therefore, the best choice is C, 90.0 mL.

Question 16

What is the molality of a glucose solution prepared by dissolving 18.0 g of glucose,C₆H₁₂O₆,in 125.9 g of water? A)7)94 × 10^-4 m B)0)143 m C)0)695 m D)0)794 m

Accepted Answer

Step 1: Calculate the moles of glucose
Molar mass of glucose (C6H12O6) = 180.18 g/mol
Number of moles of glucose = 18.0 g / 180.18 g/mol = 0.1 mol

Step 2: Calculate the mass of water in kg
Mass of water = 125.9 g = 0.1259 kg

Step 3: Calculate the molality
Molality = moles of solute / mass of solvent in kg
Molality = 0.1 mol / 0.1259 kg = 0.794 m

Therefore, the molality of the glucose solution is 0.794 m. The correct answer is D.

Question 17

A solution is prepared by dissolving 17.75 g sulfuric acid,H₂SO₄,in enough water to make 100.0 mL of solution.If the density of the solution is 1.1094 g/mL,what is the molality? A)0)1775 m H₂SO₄ B)0)1810 m H₂SO₄ C)1)810 m H₂SO₄ D)1)940 m H₂SO₄

Accepted Answer

First, we need to convert the mass of sulfuric acid to moles:

Mr(H2SO4) = 1(2) + 32 + 4(16) = 98 g/mol

moles of H2SO4 = mass/molar mass = 17.75/98 = 0.1807 mol

Next, we need to calculate the mass of the solution:

mass of solution = volume x density = 100.0 mL x 1.1094 g/mL = 110.94 g

Now we can calculate the molality:

molality = moles of solute/mass of solvent (in kg)

mass of solvent = mass of solution - mass of solute = 110.94 g - 17.75 g = 93.19 g = 0.09319 kg

molality = 0.1807 mol/0.09319 kg = 1.940 m

Therefore, the answer is D.

Question 18

What volume of 0.716 M KBr solution is needed to provide 10.5 g of KBr?
A)7)52 mL
B)14.7 mL
C)63.2 mL
D)123 mL

Accepted Answer

The answer of What volume of 0.716 M KBr solution...

Question 19

A solution is 2.25% by weight NaHCO₃.How many grams of NaHCO₃ are in 450.0 g of solution? A)0)500 g B)10.1 g C)200 g D)225 g

Accepted Answer

To find the grams of NaHCO₃ in the solution, multiply the total weight of the solution by the percentage (in decimal form) of NaHCO₃: 450.0 g * 0.0225 = 10.125 g, which rounds to 10.1 g.

Question 20

A solution is prepared by dissolving 17.75 g sulfuric acid,H₂SO₄,in enough water to make 100.0 mL of solution.If the density of the solution is 1.1094 g/mL,what is the molarity? A)0)1775 M H₂SO₄ B)0)1810 M H₂SO₄ C)1)810 M H₂SO₄ D)1)940 M H₂SO₄

Accepted Answer

The answer of A solution is prepared by dissolving 17.75...

Quiz 11: Solutions and Their Properties

To make a 2.00 m solution,one could take 2.00 moles of solute and add

To make a 2.0 M solution,one could take 2.00 moles of solute and add

Aqueous solutions of 30% (by weight) hydrogen peroxide,H₂O₂,are used to oxidize metals or organic molecules in chemical reactions.Given that the density of the solution is 1.11 g/mL,calculate the molarity.

What molality of pentane is obtained by dissolving 5.0 g pentane,C₅H₁₂,in 245.0 g hexane,C₆H₁₄?

A solution is prepared by dissolving 171 g of CdCl₂ in enough water to make exactly 250.0 mL of solution.If the density of the solution is 1.556 g/mL,what is the weight percent of CdCl₂ in the solution?

A solution is prepared by dissolving 17.75 g sulfuric acid,H₂SO₄,in enough water to make exactly 100.0 mL of solution.If the density of the solution is 1.1094 g/mL,what is the weight % H₂SO₄ in the solution?

Sodium hydroxide is available commercially as a 50.0% by weight aqueous solution.Calculate the molality of this sodium hydroxide solution.

How much water must be added to 42.0 g of CaCl₂ to produce a solution that is 35.0 wt% CaCl₂?

Aqueous solutions of 30.0% (by weight) hydrogen peroxide,H₂O₂,are used to oxidize metals or organic molecules in chemical reactions.Calculate the molality of this solution.

A solution is prepared by dissolving 171 g of CdCl₂ in enough water to make 250.0 mL of solution.If the density of the solution is 1.556 g/mL,what is the molarity of the solution?

What is the weight percent of a caffeine solution made by dissolving 4.35 g of caffeine,C₈H₁₀N₄O₂,in 75 g of benzene,C₆H₆?

What is the weight percent of vitamin C in a solution made by dissolving 1.30 g of vitamin C,C₆H₈O₆,in 55.0 g of water?

Sodium hydroxide is available commercially as a 50.0% by weight aqueous solution.The density of the solution is 1.53 g/mL.Calculate the molarity of this sodium hydroxide solution.

How many grams of KBr are required to make 650.mL of a 0.115 M KBr solution?

What volume of 3.00 M CH₃OH solution is needed to provide 0.270 mol of CH₃OH?

What is the molality of a glucose solution prepared by dissolving 18.0 g of glucose,C₆H₁₂O₆,in 125.9 g of water?

A solution is prepared by dissolving 17.75 g sulfuric acid,H₂SO₄,in enough water to make 100.0 mL of solution.If the density of the solution is 1.1094 g/mL,what is the molality?

What volume of 0.716 M KBr solution is needed to provide 10.5 g of KBr?

A solution is 2.25% by weight NaHCO₃.How many grams of NaHCO₃ are in 450.0 g of solution?

A solution is prepared by dissolving 17.75 g sulfuric acid,H₂SO₄,in enough water to make 100.0 mL of solution.If the density of the solution is 1.1094 g/mL,what is the molarity?

Quiz 11: Solutions and Their Properties

To make a 2.00 m solution,one could take 2.00 moles of solute and add

To make a 2.0 M solution,one could take 2.00 moles of solute and add

Aqueous solutions of 30% (by weight) hydrogen peroxide,H2O2,are used to oxidize metals or organic molecules in chemical reactions.Given that the density of the solution is 1.11 g/mL,calculate the molarity.

What molality of pentane is obtained by dissolving 5.0 g pentane,C5H12,in 245.0 g hexane,C6H14?

A solution is prepared by dissolving 171 g of CdCl2 in enough water to make exactly 250.0 mL of solution.If the density of the solution is 1.556 g/mL,what is the weight percent of CdCl2 in the solution?

A solution is prepared by dissolving 17.75 g sulfuric acid,H2SO4,in enough water to make exactly 100.0 mL of solution.If the density of the solution is 1.1094 g/mL,what is the weight % H2SO4 in the solution?

Sodium hydroxide is available commercially as a 50.0% by weight aqueous solution.Calculate the molality of this sodium hydroxide solution.

How much water must be added to 42.0 g of CaCl2 to produce a solution that is 35.0 wt% CaCl2?

Aqueous solutions of 30.0% (by weight) hydrogen peroxide,H2O2,are used to oxidize metals or organic molecules in chemical reactions.Calculate the molality of this solution.

A solution is prepared by dissolving 171 g of CdCl2 in enough water to make 250.0 mL of solution.If the density of the solution is 1.556 g/mL,what is the molarity of the solution?

What is the weight percent of a caffeine solution made by dissolving 4.35 g of caffeine,C8H10N4O2,in 75 g of benzene,C6H6?

What is the weight percent of vitamin C in a solution made by dissolving 1.30 g of vitamin C,C6H8O6,in 55.0 g of water?