Hydrogen iodide decomposes at 800 K via a second-order process to produce hydrogen and iodine according to the following chemical equation.
2 HI(g) → H2(g) + I2(g)
At 800 K it takes 142 seconds for the initial concentration of HI to decrease from 6.75 × 10-2 M to 3.50 × 10-2 M.What is the rate constant for the reaction at this temperature?
A) 5) 12 × 10-4 M-1s-1
B) 9) 69 × 10-2 M-1s-1
C) 10.3 M-1s-1
D) 1) 95 × 103 M-1s-1
Correct Answer:
Verified
Q32: A researcher needs 5.00 mg of 128Ba
Q42: The reaction: 2 HI → H2 +
Q48: A plot of 1/[BrO-] vs time is
Q50: The second-order reaction,2 Mn(CO)5 → Mn2(CO)10 has
Q65: If the units for rate are M
Q71: A mechanism for a naturally occurring reaction
Q71: The elementary reaction representing the formation of
Q72: For the zeroth-order reaction: A → products,what
Q74: For the zeroth-order reaction: C → products,-Δ[C]/Δt
Q80: A mechanism for a naturally occurring reaction
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents