The Second-Order Reaction,2 Mn(CO)₅ → Mn₂(CO)₁₀ Has a Rate Constant

The second-order reaction,2 Mn(CO) ₅ → Mn₂(CO) ₁₀ has a rate constant equal to 3.0 × 10⁹ M^-1s^-1 at 25°C.If the initial concentration of Mn(CO) ₅ is 1.0 × 10^-5 M,how long will it take for 90.% of the reactant to disappear?

A) 3.3 × 10^-16 s
B) 3.7 × 10^-15 s
C) 3.0 × 10^-4 s
D) 3.0 × 10³ s