When 0.350 grams of anhydrous copper(II)sulfate is exposed to moist air,it absorbs water.If the hydrated copper compound has a mass of 0.508 grams,what is the chemical formula of the hydrate? A)CuSO₄∙ 2H₂O B)CuSO₄∙ 3H₂O C)CuSO₄∙ 4H₂O D)CuSO₄∙ 5H₂O

Question

Quizplus · Accepted Answer

To determine the chemical formula of the hydrate, we need to calculate the number of water molecules attached to each CuSO4 molecule in the hydrated compound.

First, we need to find the number of moles of CuSO4 in 0.350 grams:

0.350 g CuSO4 x (1 mol CuSO4/ 159.62 g CuSO4) = 0.00219 mol CuSO4

Next, we need to find the number of moles of water that were absorbed:

(0.508 g hydrated sample - 0.350 g anhydrous sample) / (18.015 g/mol H2O) = 0.00876 mol H2O

Now we can divide the number of moles of water by the number of moles of CuSO4 to get the ratio of water molecules to CuSO4 molecules:

0.00876 mol H2O / 0.00219 mol CuSO4 = 4

Therefore, the chemical formula of the hydrate is CuSO4·4H2O, which corresponds to choice C.

When 0350 Grams of Anhydrous Copper(II)sulfate Is Exposed to Moist Air,it