The reaction of HCl with NaOH is represented by the equation
HCl(aq) + NaOH(aq) → NaCl(aq) + H₂O(l)
What volume of 0.417 M HCl is required to titrate 11.9 mL of 0.151 M NaOH?

Question

The reaction of HCl with NaOH is represented by the equation HCl(aq)+ NaOH(aq)→ NaCl(aq)+ H₂O(l) What volume of 0.417 M HCl is required to titrate 11.9 mL of 0.151 M NaOH?

Quizplus · Accepted Answer

1. Write a balanced chemical equation:
HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)

2. Determine the mole ratio of reactants:
From the equation, the mole ratio of HCl to NaOH is 1:1.

3. Calculate the moles of NaOH:
moles NaOH = concentration × volume
moles NaOH = 0.151 mol/L × 11.9 mL × 1 L/1000 mL
moles NaOH = 1.80 × 10^-3 mol

4. Determine the volume of HCl needed:
moles HCl = moles NaOH
volume HCl = moles HCl ÷ concentration
volume HCl = 1.80 × 10^-3 mol ÷ 0.417 mol/L
volume HCl = 4.30 mL ≈ 4.3 mL

Therefore, the best choice is C, 4.3 mL.

The Reaction of HCl with NaOH Is Represented by the Equation