A 20.00-mL sample of a weak base is titrated with 0.0568 M HCl.At the endpoint,it is found that 17.88 mL of titrant was used.What was the concentration of the weak base?

Question

Quizplus · Accepted Answer

The concentration of the weak base can be found using the formula $C_1V_1 = C_2V_2$, where $C_1$ and $V_1$ are the concentration and volume of the acid, and $C_2$ and $V_2$ are the concentration and volume of the base, respectively. Rearranging for $C_2$, we get $C_2 = \frac{C_1V_1}{V_2}$. Plugging in the given values, $C_2 = \frac{0.0568 \, \text{M} \times 17.88 \, \text{mL}}{20.00 \, \text{mL}} = 0.0507 \, \text{M}$.

A 2000-ML Sample of a Weak Base Is Titrated with 0