What is the volume occupied by a mixture of 0.774 mol of N₂ and 0.774 mol of O₂ gases at 1.04 atm and 25.6°C? A)1.1 × 10³ L B)36.5 L C)1.56 L D)3.12 L E)18.2 L

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Using the ideal gas law, PV = nRT, where P = 1.04 atm, n = 0.774 mol + 0.774 mol = 1.548 mol, R = 0.0821 L·atm/mol·K, and T = 25.6°C = 298.75 K, the volume V can be calculated as V = nRT/P = (1.548 mol)(0.0821 L·atm/mol·K)(298.75 K) / 1.04 atm ≈ 36.5 L.

What Is the Volume Occupied by a Mixture of 0