The partial pressures of CH₄,N₂,and O₂ in a sample of gas were found to be 183 mmHg,443 mmHg,and 693 mmHg,respectively.What is the mole fraction of nitrogen? A)21.7 B)0.912 C)0.525 D)0.410 E)0.336

Question

Quizplus · Accepted Answer

The mole fraction of a component in a mixture is calculated by dividing the partial pressure of that component by the total pressure of the mixture. The total pressure is the sum of the partial pressures of all components. For nitrogen (N₂), the partial pressure is 443 mmHg. The total pressure is the sum of the partial pressures of CH₄ (183 mmHg), N₂ (443 mmHg), and O₂ (693 mmHg), which equals 1319 mmHg. Therefore, the mole fraction of nitrogen (N₂) is 443 mmHg / 1319 mmHg = 0.336.

The Partial Pressures of CH4,N2,and O2 in a Sample of Gas

The Partial Pressures of CH₄,N₂,and O₂ in a Sample of Gas