A 86.9-g sample of chromium (s = 0.447 J/(g ∙ °C)),initially at 338.33°C,is added to an insulated vessel containing 189.9 g of water (s = 4.18 J/(g ∙ °C)),initially at 16.17°C.At equilibrium,the final temperature of the metal-water mixture is 28.06°C.How much heat was absorbed by the water? The heat capacity of the vessel is 0.220 kJ/°C.

Question

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Explanation:Heat lost by chromium = m(s)(T_i - T_f) = (86.9 g)(0.447 J/(g ∙ °C))(338.33°C - 28.06°C) = 10.4 kJHeat gained by water = m(s)(T_f - T_i) = (189.9 g)(4.18 J/(g ∙ °C))(28.06°C - 16.17°C) = 9.43 kJHeat gained by calorimeter = (0.220 kJ/°C)(28.06°C - 16.17°C) = 2.63 kJTotal heat gained = 9.43 kJ + 2.63 kJ = 12.06 kJ

A 869-G Sample of Chromium (S = 0