When 9.42 g of methane (CH₄)is burned in a bomb calorimeter (heat capacity = 2.677 × 10³ J/°C),the temperature rises from 24.00 to 27.08°C.How much heat is absorbed by the calorimeter? CH₄(g)+ 2O₂(g)→ CO₂(g)+ 2H₂O(l); ΔH° = -1283.8 kJ A)745 kJ B)4.84 × 10³ kJ C)8.24 kJ D)753 kJ E)1.28 × 10³ kJ

Question

Quizplus · Accepted Answer

The heat absorbed by the calorimeter is calculated using the formula q = C × ΔT, where C is the heat capacity and ΔT is the change in temperature. Here, q = 2.677 × 10³ J/°C × (27.08°C - 24.00°C) = 8.24 kJ.

When 942 G of Methane (CH4)is Burned in a Bomb Calorimeter

When 942 G of Methane (CH₄)is Burned in a Bomb Calorimeter