When 0.0500 mol of HCl(aq)is reacted with 0.0500 mol of NaOH(aq)in 50.0 mL of water,the temperature of the solution increases by 5.99°C.What is the enthalpy of reaction for the following thermochemical equation? HCl(aq)+ NaOH(aq)→ NaCl(aq)+ H₂O(l) Assume that the heat capacity of the solution and calorimeter is 465.4 J/°C. A)0.139 kJ B)55.8 kJ C)2.791 kJ D)-55.8 kJ E)2.79 kJ

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Quizplus · Accepted Answer

The enthalpy change can be calculated using q = mcΔT. Here, q = 465.4 J/°C * 5.99°C = 2787.746 J or 2.787746 kJ. Since the reaction is exothermic, the enthalpy change is negative, so the answer is -55.8 kJ/mol when adjusted for moles.

When 00500 Mol of HCl(aq)is Reacted with 0