Given: Fe₂O₃(s)+ 3CO(g)→ 2Fe(s)+ 3CO₂(g); ΔH° = -26.8 kJ FeO(s)+ CO(g)→ Fe(s)+ CO₂(g); ΔH° = -16.5 kJ Determine ΔH° for the following thermochemical equation. Fe₂O₃(s)+ CO(g)→ 2FeO(s)+ CO₂(g) A)6.2 kJ B)10.3 kJ C)22.7 kJ D)-10.3 kJ E)-43.3 kJ

Question

Quizplus · Accepted Answer

To find ΔH° for the desired reaction, we manipulate the given reactions. The first reaction is divided by 3, and the second reaction is reversed and multiplied by 2. This gives:1/3(Fe3O4(s) + 3CO(g) → 2Fe(s) + 3CO2(g); ΔH° = -26.8/3 kJ)2(Fe(s) + CO2(g) → FeO(s) + CO(g); ΔH° = 2(16.5) kJ)Adding these adjusted reactions cancels out 2Fe(s) and 2CO2(g), resulting in:Fe3O4(s) + CO(g) → 2FeO(s) + CO2(g); ΔH° = (-26.8/3) + 2(16.5) kJ = 6.2 kJ

Given: Fe2O3(s)+ 3CO(g)→ 2Fe(s)+ 3CO2(g); ΔH° = -26.8 KJ

Given: Fe₂O₃(s)+ 3CO(g)→ 2Fe(s)+ 3CO₂(g); ΔH° = -26.8 KJ