Exactly 209.2 J will raise the temperature of 10.0 g of a metal from 25.0°C to 60.0°C.What is the specific heat capacity of the metal?
A)0.598 J/(g ∙ °C)
B)1.67 J/(g ∙ °C)
C)14.7 J/(g ∙ °C)
D)50.0 J/(g ∙ °C)
E)none of these

Question

Quizplus · Accepted Answer

The formula for calculating the amount of heat required to raise the temperature of a substance is:

q = m * c * ΔT

where q is the heat energy, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

We can rearrange this formula to solve for c:

c = q / (m * ΔT)

Plugging in the given values:

c = 209.2 J / (10.0 g * (60.0°C - 25.0°C))
c = 0.598 J/(g ∙ °C)

Therefore, the specific heat capacity of the metal is 0.598 J/(g ∙ °C) or choice A.