What is the standard enthalpy of formation of liquid methylamine (CH₃NH₂) ?
C(s) + O₂(g) → CO₂(g) ; ΔH° = -393.5 kJ
2H₂O(l) → 2H₂(g) + O₂(g) ; ΔH° = 571.6 kJ
N₂(g) + O₂(g) → NO₂(g) ; ΔH° = 33.10 kJ
4CH₃NH₂(l) + 13O₂(g) → 4CO₂(g) + 4NO₂(g) + 10H₂O(l) ; ΔH° = -4110.4 kJ

Question

What is the standard enthalpy of formation of liquid methylamine (CH₃NH₂) ?
C(s) + O₂(g) → CO₂(g) ; ΔH° = -393.5 kJ
2H₂O(l) → 2H₂(g) + O₂(g) ; ΔH° = 571.6 kJ

What is the standard enthalpy of formation of liquid methylamine (CH<sub>3</sub>NH<sub>2</sub>) ? C(s) + O<sub>2</sub>(g) → CO<sub>2</sub>(g) ; ΔH° = -393.5 kJ 2H<sub>2</sub>O(l) → 2H<sub>2</sub>(g) + O<sub>2</sub>(g) ; ΔH° = 571.6 kJ N<sub>2</sub>(g) + O<sub>2</sub>(g) → NO<sub>2</sub>(g) ; ΔH° = 33.10 kJ 4CH<sub>3</sub>NH<sub>2</sub>(l) + 13O<sub>2</sub>(g) → 4CO<sub>2</sub>(g) + 4NO<sub>2</sub>(g) + 10H<sub>2</sub>O(l) ; ΔH° = -4110.4 kJ A) +3899.2 kJ/mol B) -3899.2 kJ/mol C) -47.3 kJ/mol D) +47.3 kJ/mol E) +3178.4 kJ

N₂(g) + O₂(g) → NO₂(g) ; ΔH° = 33.10 kJ
4CH₃NH₂(l) + 13O₂(g) → 4CO₂(g) + 4NO₂(g) + 10H₂O(l) ; ΔH° = -4110.4 kJ

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The Answer of What is the standard enthalpy of formation of liquid methylamine (CH₃NH₂)? C(s)+ O₂(g)→ CO₂(g); ΔH° = -393.5 kJ 2H₂O(l)→ 2H₂(g)+ O₂(g); ΔH° = 571.6 kJ N₂(g)+ O₂(g)→ NO₂(g); ΔH° = 33.10 kJ 4CH₃NH₂(l)+ 13O₂(g)→ 4CO₂(g)+ 4NO₂(g)+ 10H₂O(l); ΔH° = -4110.4 kJ

What Is the Standard Enthalpy of Formation of Liquid Methylamine