The enthalpy change at 1 atm of which reaction corresponds to the standard enthalpy of formation of solid potassium bromate,KBrO3?
A) K(s) + Br(g) + 3O(g) → KBrO3(s)
B) K(g) + Br(g) + 3O(g) → KBrO3(s)
C) K(g) +
Br2(g) +
O2(g) → KBrO3(s)
D) K(s) +
Br2(l) +
O2(g) → KBrO3(s)
E) K(s) +
Br2(g) +
O2(g) → KBrO3(s)
Correct Answer:
Verified
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