What is the molality of a solution that contains 9.16 g of glucose,C₆H₁₂O₆,in 228.5 g of water? A)0.223 m B)0.0509 m C)0.00399 m D)0.0116 m E)0.0401 m

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Quizplus · Accepted Answer

Molality (m) is calculated using the formula $m = \frac{\text{moles of solute}}{\text{kg of solvent}}$. The molar mass of glucose (C6H12O6) is approximately 180.16 g/mol. Moles of glucose = $\frac{9.16 \text{ g}}{180.16 \text{ g/mol}} = 0.0509 \text{ mol}$. The mass of water is 228.5 g, which is 0.2285 kg. Thus, molality = $\frac{0.0509 \text{ mol}}{0.2285 \text{ kg}} = 0.2227 \text{ m}$, which rounds to 0.223 m.

What Is the Molality of a Solution That Contains 9