What is the mole fraction of urea,CO(NH₂)₂,in a solution prepared by dissolving 4.0 g of urea in 32.0 g of methanol,CH₃OH? A)0.89 B)0.11 C)0.063 D)0.94 E)0.19

Question

Quizplus · Accepted Answer

First, we need to find the moles of urea and methanol in the solution.

Moles of urea = mass / molar mass = 4.0 g / 60.06 g/mol = 0.0666 mol

Moles of methanol = mass / molar mass = 32.0 g / 32.04 g/mol = 0.9997 mol

Next, we can calculate the total moles of solute and solvent:

Total moles = moles of urea + moles of methanol = 0.0666 mol + 0.9997 mol = 1.0663 mol

Finally, we can find the mole fraction of urea:

Mole fraction of urea = moles of urea / total moles = 0.0666 mol / 1.0663 mol ≈ 0.0626

Therefore, the mole fraction of urea is approximately 0.063. The closest answer choice is C, 0.063.

What Is the Mole Fraction of Urea,CO(NH2)2,in a Solution Prepared

What Is the Mole Fraction of Urea,CO(NH₂)₂,in a Solution Prepared