The complete mechanism for a reaction is considered to occur in two steps,one of which is slow and the other fast:
A + 2B → C + D slow
A + C → E + F fast
What is the rate law predicted by this mechanism?

Question

Quizplus · Accepted Answer

The rate law for a reaction mechanism is determined by the slow step, as it is the rate-determining step. In this case, the slow step is A + 2B → C + D, so the rate law is based on the concentrations of the reactants in this step, which are A and B. Since B is a reactant with a stoichiometric coefficient of 2, it appears squared in the rate law, leading to Rate = k[A][B]^2.

The Complete Mechanism for a Reaction Is Considered to Occur