Solved

The Reaction CHCl3(g)+ Cl2(g) CCl4(g)+ HCl(g)has Been Proposed to Occur

Question 100

Multiple Choice

The reaction CHCl3(g) + Cl2(g) The reaction CHCl<sub>3</sub>(g) + Cl<sub>2</sub>(g)    CCl<sub>4</sub>(g) + HCl(g) has been proposed to occur by the following mechanism. Cl<sub>2</sub>   2Cl fast equilibrium CHCl<sub>3</sub> + Cl   HCl + CCl<sub>3</sub> slow step CCl<sub>3</sub> + Cl   CCl<sub>4</sub> fast What is the rate law predicted by this mechanism? A) Rate = k<sub>exp</sub>[CHCl<sub>3</sub>][Cl<sub>2</sub>] B) Rate = k<sub>2</sub>[CHCl<sub>3</sub>][Cl] C) Rate = k<sub>1</sub>[Cl<sub>2</sub>] D) Rate = k<sub>3</sub>[CCl<sub>3</sub>][Cl] E) Rate = k<sub>2</sub>(k<sub>1</sub>/k<sub>-1</sub>) <sup>1/2</sup>[CHCl<sub>3</sub>][Cl<sub>2</sub>]<sup>1/2</sup> CCl4(g) + HCl(g) has been proposed to occur by the following mechanism.
Cl2 The reaction CHCl<sub>3</sub>(g) + Cl<sub>2</sub>(g)    CCl<sub>4</sub>(g) + HCl(g) has been proposed to occur by the following mechanism. Cl<sub>2</sub>   2Cl fast equilibrium CHCl<sub>3</sub> + Cl   HCl + CCl<sub>3</sub> slow step CCl<sub>3</sub> + Cl   CCl<sub>4</sub> fast What is the rate law predicted by this mechanism? A) Rate = k<sub>exp</sub>[CHCl<sub>3</sub>][Cl<sub>2</sub>] B) Rate = k<sub>2</sub>[CHCl<sub>3</sub>][Cl] C) Rate = k<sub>1</sub>[Cl<sub>2</sub>] D) Rate = k<sub>3</sub>[CCl<sub>3</sub>][Cl] E) Rate = k<sub>2</sub>(k<sub>1</sub>/k<sub>-1</sub>) <sup>1/2</sup>[CHCl<sub>3</sub>][Cl<sub>2</sub>]<sup>1/2</sup>
2Cl fast equilibrium
CHCl3 + Cl The reaction CHCl<sub>3</sub>(g) + Cl<sub>2</sub>(g)    CCl<sub>4</sub>(g) + HCl(g) has been proposed to occur by the following mechanism. Cl<sub>2</sub>   2Cl fast equilibrium CHCl<sub>3</sub> + Cl   HCl + CCl<sub>3</sub> slow step CCl<sub>3</sub> + Cl   CCl<sub>4</sub> fast What is the rate law predicted by this mechanism? A) Rate = k<sub>exp</sub>[CHCl<sub>3</sub>][Cl<sub>2</sub>] B) Rate = k<sub>2</sub>[CHCl<sub>3</sub>][Cl] C) Rate = k<sub>1</sub>[Cl<sub>2</sub>] D) Rate = k<sub>3</sub>[CCl<sub>3</sub>][Cl] E) Rate = k<sub>2</sub>(k<sub>1</sub>/k<sub>-1</sub>) <sup>1/2</sup>[CHCl<sub>3</sub>][Cl<sub>2</sub>]<sup>1/2</sup>
HCl + CCl3 slow step
CCl3 + Cl The reaction CHCl<sub>3</sub>(g) + Cl<sub>2</sub>(g)    CCl<sub>4</sub>(g) + HCl(g) has been proposed to occur by the following mechanism. Cl<sub>2</sub>   2Cl fast equilibrium CHCl<sub>3</sub> + Cl   HCl + CCl<sub>3</sub> slow step CCl<sub>3</sub> + Cl   CCl<sub>4</sub> fast What is the rate law predicted by this mechanism? A) Rate = k<sub>exp</sub>[CHCl<sub>3</sub>][Cl<sub>2</sub>] B) Rate = k<sub>2</sub>[CHCl<sub>3</sub>][Cl] C) Rate = k<sub>1</sub>[Cl<sub>2</sub>] D) Rate = k<sub>3</sub>[CCl<sub>3</sub>][Cl] E) Rate = k<sub>2</sub>(k<sub>1</sub>/k<sub>-1</sub>) <sup>1/2</sup>[CHCl<sub>3</sub>][Cl<sub>2</sub>]<sup>1/2</sup>
CCl4 fast
What is the rate law predicted by this mechanism?


A) Rate = kexp[CHCl3][Cl2]
B) Rate = k2[CHCl3][Cl]
C) Rate = k1[Cl2]
D) Rate = k3[CCl3][Cl]
E) Rate = k2(k1/k-1) 1/2[CHCl3][Cl2]1/2

Correct Answer:

verifed

Verified

Unlock this answer now
Get Access to more Verified Answers free of charge

Related Questions

Unlock this Answer For Free Now!

View this answer and more for free by performing one of the following actions

qr-code

Scan the QR code to install the App and get 2 free unlocks

upload documents

Unlock quizzes for free by uploading documents