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For Which of the Following Equilibria Does Kc = Kp

Question 39

Multiple Choice

For which of the following equilibria does Kc = Kp?


A) N2(g) + 3H2(g) For which of the following equilibria does K<sub>c</sub> = K<sub>p</sub>? A) N<sub>2</sub>(g) + 3H<sub>2</sub>(g) 2NH<sub>3</sub>(g) B) CO(g) + H<sub>2</sub>O(g) CO<sub>2</sub>(g) + H<sub>2</sub>(g) C) CO(g) + 3H<sub>2</sub>(g) CH<sub>4</sub>(g) + H<sub>2</sub>O(g) D) CaO(s) + CO<sub>2</sub>(g) CaCO<sub>3</sub>(s) E) HBr(g) 1/2H<sub>2</sub>(g) + 1/2Br<sub>2</sub>(l) 2NH3(g)
B) CO(g) + H2O(g) For which of the following equilibria does K<sub>c</sub> = K<sub>p</sub>? A) N<sub>2</sub>(g) + 3H<sub>2</sub>(g) 2NH<sub>3</sub>(g) B) CO(g) + H<sub>2</sub>O(g) CO<sub>2</sub>(g) + H<sub>2</sub>(g) C) CO(g) + 3H<sub>2</sub>(g) CH<sub>4</sub>(g) + H<sub>2</sub>O(g) D) CaO(s) + CO<sub>2</sub>(g) CaCO<sub>3</sub>(s) E) HBr(g) 1/2H<sub>2</sub>(g) + 1/2Br<sub>2</sub>(l) CO2(g) + H2(g)
C) CO(g) + 3H2(g) For which of the following equilibria does K<sub>c</sub> = K<sub>p</sub>? A) N<sub>2</sub>(g) + 3H<sub>2</sub>(g) 2NH<sub>3</sub>(g) B) CO(g) + H<sub>2</sub>O(g) CO<sub>2</sub>(g) + H<sub>2</sub>(g) C) CO(g) + 3H<sub>2</sub>(g) CH<sub>4</sub>(g) + H<sub>2</sub>O(g) D) CaO(s) + CO<sub>2</sub>(g) CaCO<sub>3</sub>(s) E) HBr(g) 1/2H<sub>2</sub>(g) + 1/2Br<sub>2</sub>(l) CH4(g) + H2O(g)
D) CaO(s) + CO2(g) For which of the following equilibria does K<sub>c</sub> = K<sub>p</sub>? A) N<sub>2</sub>(g) + 3H<sub>2</sub>(g) 2NH<sub>3</sub>(g) B) CO(g) + H<sub>2</sub>O(g) CO<sub>2</sub>(g) + H<sub>2</sub>(g) C) CO(g) + 3H<sub>2</sub>(g) CH<sub>4</sub>(g) + H<sub>2</sub>O(g) D) CaO(s) + CO<sub>2</sub>(g) CaCO<sub>3</sub>(s) E) HBr(g) 1/2H<sub>2</sub>(g) + 1/2Br<sub>2</sub>(l) CaCO3(s)
E) HBr(g) For which of the following equilibria does K<sub>c</sub> = K<sub>p</sub>? A) N<sub>2</sub>(g) + 3H<sub>2</sub>(g) 2NH<sub>3</sub>(g) B) CO(g) + H<sub>2</sub>O(g) CO<sub>2</sub>(g) + H<sub>2</sub>(g) C) CO(g) + 3H<sub>2</sub>(g) CH<sub>4</sub>(g) + H<sub>2</sub>O(g) D) CaO(s) + CO<sub>2</sub>(g) CaCO<sub>3</sub>(s) E) HBr(g) 1/2H<sub>2</sub>(g) + 1/2Br<sub>2</sub>(l) 1/2H2(g) + 1/2Br2(l)

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