Exactly 1.0 mol N₂O₄ is placed in an empty 1.0-L container and allowed to reach equilibrium described by the equation N₂O₄(g) 2NO₂(g) .
If at equilibrium the N₂O₄ is 28.0% dissociated,what is the value of the equilibrium constant,K_c,for the reaction under these conditions?

Question

Exactly 1.0 mol N₂O₄ is placed in an empty 1.0-L container and allowed to reach equilibrium described by the equation N₂O₄(g) Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and allowed to reach equilibrium described by the equation N2O4(g) 2NO2(g) . If at equilibrium the N2O4 is 28.0% dissociated,what is the value of the equilibrium constant,Kc,for the reaction under these conditions? A) 0.44 B) 2.3 C) 0.31 D) 0.78 E) 0.11

Exactly 1.0 mol N<sub>2</sub>O<sub>4</sub> is placed in an empty 1.0-L container and allowed to reach equilibrium described by the equation N<sub>2</sub>O<sub>4</sub>(g) 2NO<sub>2</sub>(g) . If at equilibrium the N<sub>2</sub>O<sub>4</sub> is 28.0% dissociated,what is the value of the equilibrium constant,K<sub>c</sub>,for the reaction under these conditions? A) 0.44 B) 2.3 C) 0.31 D) 0.78 E) 0.11

2NO₂(g) .
If at equilibrium the N₂O₄ is 28.0% dissociated,what is the value of the equilibrium constant,K_c,for the reaction under these conditions?

Quizplus · Accepted Answer

The Answer of Exactly 1.0 mol N₂O₄ is placed in an empty 1.0-L container and allowed to reach equilibrium described by the equation N₂O₄(g) 2NO₂(g). If at equilibrium the N₂O₄ is 28.0% dissociated,what is the value of the equilibrium constant,K_c,for the reaction under these conditions?

Exactly 10 Mol N2O4 Is Placed in an Empty 1

Exactly 10 Mol N₂O₄ Is Placed in an Empty 1