Carbon monoxide is toxic because it can successfully compete with oxygen for hemoglobin (Hb) sites according to the following equilibrium:
Hb(O₂) ₄(aq) + 4CO(g)
Hb(CO) ₄(aq) + 4O₂(g)
From Le Châtelier's principle,CO poisoning is reversed by

Question

Carbon monoxide is toxic because it can successfully compete with oxygen for hemoglobin (Hb) sites according to the following equilibrium:
Hb(O₂) ₄(aq) + 4CO(g)

Carbon monoxide is toxic because it can successfully compete with oxygen for hemoglobin (Hb) sites according to the following equilibrium: Hb(O<sub>2</sub>) <sub>4</sub>(aq) + 4CO(g) Hb(CO) <sub>4</sub>(aq) + 4O<sub>2</sub>(g) From Le Châtelier's principle,CO poisoning is reversed by A) increasing the O<sub>2</sub> pressure. B) decreasing the amount of Hb. C) increasing the CO<sub>2</sub> pressure. D) increasing the CO pressure. E) increasing the amount of Hb.

Hb(CO) ₄(aq) + 4O₂(g)
From Le Châtelier's principle,CO poisoning is reversed by

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The Answer of Carbon monoxide is toxic because it can successfully compete with oxygen for hemoglobin (Hb)sites according to the following equilibrium: Hb(O₂)₄(aq)+ 4CO(g) Hb(CO)₄(aq)+ 4O₂(g) From Le Châtelier's principle,CO poisoning is reversed by

Carbon Monoxide Is Toxic Because It Can Successfully Compete with Oxygen