For a 0.10 M solution of glutaric acid,HO₂C(CH₂)₃CO₂H (Ka₁ = 4.6 × 10^-5,Ka₂ = 3.9 × 10^-6),rank the following species in order of increasing equilibrium concentration. A)H₃O⁺

Question

For a 0.10 M solution of glutaric acid,HO₂C(CH₂)₃CO₂H (Ka₁ = 4.6 × 10^-5,Ka₂ = 3.9 × 10^-6),rank the following species in order of increasing equilibrium concentration. A)H₃O⁺ < ^-O₂C(CH₂)₃COO^- < HO₂C(CH₂)₃COO^- < OH^- < HO₂C(CH₂)₃CO₂H B)OH^- < ^-O₂C(CH₂)₃COO^- < H₃O⁺ < HO₂C(CH₂)₃COO^- < HO₂C(CH₂)₃CO₂H C)OH^- < ^-O₂C(CH₂)₃COO^- < HO₂C(CH₂)₃COO^- < H₃O⁺ < HO₂C(CH₂)₃CO₂H D)H₃O⁺ < HO₂C(CH₂)₃CO₂H < HO₂C(CH₂)₃COO^- < ^-O₂C(CH₂)₃COO^- < OH^- E)OH^- < ^-O₂C(CH₂)₃COO^- < HO₂C(CH₂)₃COO^- < HO₂C(CH₂)₃CO₂H < H₃O⁺

Quizplus · Accepted Answer

Glutaric acid is a diprotic acid, meaning it can donate two protons. The species are ranked based on their formation in the dissociation process. The fully protonated form (H2A) has the highest concentration initially. As it donates protons, the concentration of the deprotonated forms (HA- and A2-) increases, but they will always be less than the fully protonated form due to the equilibrium favoring the left side for weak acids. The concentration of OH- (hydroxide ion) is the lowest because it is not directly produced by the dissociation of glutaric acid but rather comes from the autoionization of water, which is minimal compared to the concentrations of the acid and its conjugate bases.

For a 010 M Solution of Glutaric Acid,HO2C(CH2)3CO2H (Ka1 = 4

For a 010 M Solution of Glutaric Acid,HO₂C(CH₂)₃CO₂H (Ka₁ = 4