What is the percent ionization at equilibrium in a 0.10 M solution of dimethylamine,(CH₃)₂NH (K_b = 5.1 × 10^-4),at 25^oC? A)6.8% B)0.51% C)0.68% D)100% E)10%

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The percent ionization can be calculated using the formula: % ionization = ([OH⁻]/[base initial]) × 100. First, calculate [OH⁻] using the Kb expression: Kb = [OH⁻]²/[base initial - OH⁻] ≈ [OH⁻]²/[base initial] for small ionization. Solving for [OH⁻] gives approximately 0.0068 M, leading to a percent ionization of about 6.8%.

What Is the Percent Ionization at Equilibrium in a 0