What is the equilibrium concentration of ammonium ion in a 0.33 M solution of ammonia (NH₃,K_b = 1.8 × 10^-5)at 25^oC? A)3.0 × 10^-14 M B)4.1 × 10^-12 M C)2.4 × 10^-3 M D)7.4 × 10^-3 M E)3.3 × 10^-1 M

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Quizplus · Accepted Answer

The equilibrium concentration of ammonium ion can be calculated using the formula for Kb: [NH4+][OH-]/[NH3] = Kb. Assuming x is the concentration of NH4+ and OH-, and [NH3] is approximately 0.33 M, solving for x gives approximately 2.4 × 10^-3 M.

What Is the Equilibrium Concentration of Ammonium Ion in a 0.33