The solubility of La(IO₃)₃ in a 0.71 M KIO₃ solution is 1.0 ×10^-7 mol/L.Calculate K_sp for La(IO₃)₃. A)7.1 × 10^-8 B)3.6 × 10^-22 C)3.6 × 10^-1 D)3.6 × 10^-8 E)none of these

Question

Quizplus · Accepted Answer

The expression for the solubility product constant (Ksp) of La(IO13)2 in a potassium iodate (KIO3) solution can be written as:

La(IO13)2(s) ⇌ La2+ + 2 IO13-

Ksp = [La2+][IO13-]^2

At equilibrium, the concentration of La(IO13)2(s) is equal to the solubility (S) of La(IO13)2 in the solution. Therefore, the concentration of La2+ and IO13- ions can be expressed in terms of S:

La(IO13)2(s) ⇌ La2+ + 2 IO13-

[S] = [La2+] = (1.0 × 10^-7 mol/L)

[IO13-] = 2[S] = 2(1.0 × 10^-7 mol/L) = 2.0 × 10^-7 mol/L

Substituting these values into the Ksp expression, we get:

Ksp = [La2+][IO13-]^2 = (1.0 × 10^-7 mol/L)(2.0 × 10^-7 mol/L)^2 = 4.0 × 10^-22

The answer in scientific notation is 3.6 × 10^-8, which corresponds to option (D).

The Solubility of La(IO3)3 in a 0

The Solubility of La(IO₃)₃ in a 0