If 275 mL of 1 × 10^-7 M AgNO₃ is mixed with 275 mL of 1 × 10^-8 M NaI,what will occur? For AgI,K_sp = 8.3 × 10^-17. A)Sodium nitrate will precipitate. B)Silver(I)nitrate will precipitate. C)Sodium iodide will precipitate. D)Silver(I)iodide will precipitate. E)No precipitate will form.

Question

Quizplus · Accepted Answer

When silver(I) nitrate (AgNO3) and sodium iodide (NaI) are combined, they undergo a double displacement reaction to form silver(I) iodide (AgI) and sodium nitrate (NaNO3). AgNO3(aq) + NaI(aq) → AgI(s) + NaNO3(aq) Since the solubility product constant (Ksp) of AgI is very small (8.3 × 10^-17), AgI will precipitate out of solution, leaving NaNO3 in solution. Therefore, the answer is (D) Silver(I)iodide will precipitate.

If 275 ML of 1 × 10-7 M AgNO3 Is

If 275 ML of 1 × 10^-7 M AgNO₃ Is