What is the concentration of Cd²⁺ in a 0.012 M Cd(NO₃)2 solution that is also 1.0 M NH₃? For Cd(NH₃)₄²⁺,K_f = 1.0 × 10⁷. A)3.5 × 10²M B)1.3 × 10^-9M C)1.5 × 10-9 M D)3.2 × 103 M E)1.2 × 10-2 M

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Quizplus · Accepted Answer

The concentration of Cd²⁺ in the solution can be calculated using the solubility product constant (Ksp) for Cd(NH₃)₄²⁺, which is given as 1.0 × 10⁷ (or 1.0 × 10^-17). Given the high concentration of NH4+ (1.0 M), the common ion effect significantly reduces the solubility of CdS in the solution. The calculation involves setting up an expression for Ksp in terms of the concentrations of the ions produced by the dissolution of CdS, and solving for the concentration of Cd2+ ions, which is equal to the solubility of CdS in this context. The correct answer reflects the solubility of CdS under these conditions, taking into account the common ion effect and the given Ksp value.

What Is the Concentration of Cd2+ in a 0

What Is the Concentration of Cd²⁺ in a 0