In the following electrochemical cell,what is the reduction half reaction?
Mn(s) | Mn2+(aq) || Fe3+(aq) ,Fe2+(aq) | Pt(s)
A) Fe3+(aq) + e− → Fe2+(aq)
B) Fe2+(aq) + e− → Fe3+(aq)
C) Fe2+(aq) + Pt(s) → Fe3+(aq) + e−
D) Mn2+(aq) → Mn(s) + 2e−
E) Mn(s) → Mn2+(aq) + 2e−
Correct Answer:
Verified
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